By D. J. Bell and F. H. George (Auth.)
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Extra resources for Applied Calculus
This was a wrong answer. Remember that for a non-uniform velocity either the magnitude, or the direction, or both, must vary. If both are constant, as in the case for motion along a straight line with uniform speed, then the velocity is uniform. Turn back to 32 45 from 38 Your answer was 4- π. This was a wrong answer. You have probably made a slight slip in your calculations, but it would be wise to check your differentiation as well. Turn back to 38 46 from 33 Your answer was 600 ft/sec. This was a wrong answer.
Turn to 67 64 from 50 Your answer was "no". This was a wrong answer. Divide the given area S into strips as before, and by considering one typical strip, deduce the inequalities y δχ > SS > (y + ôy) δχ. Then proceed as before to determine whether y = dS/dx. Turn back to 50 65 from 58 Your answer was 6 ft. This was a wrong answer. Your answer seems to suggest that you have differentiated your integrand instead of integrating it. Check this first. If you have integrated correctly then your error may lie in the numerical work, so check that as well.
H. as required. Turn to 79 73 from 78 When a particle moves in a straight line the magnitude of the velocity is the speed of the particle and the direction of motion is constant but it is very important to distinguish between the two. Velocity requires both speed and a direction to specify it. Turn to 84 74 from 71 No. You have chosen the equation v = u + at. This is not the correct answer. Although the equation v = u + at contains u and v, which are known, and the quantity a, which is required, it also contains the variable i, which is a second unknown.
Applied Calculus by D. J. Bell and F. H. George (Auth.)